Optimal. Leaf size=468 \[ \frac {3 a^9 \left (1+\frac {b \sqrt [3]{x}}{a}\right ) \left (a^2+2 a b \sqrt [3]{x}+b^2 x^{2/3}\right )^p}{b^9 (1+2 p)}-\frac {12 a^9 \left (1+\frac {b \sqrt [3]{x}}{a}\right )^2 \left (a^2+2 a b \sqrt [3]{x}+b^2 x^{2/3}\right )^p}{b^9 (1+p)}+\frac {84 a^9 \left (1+\frac {b \sqrt [3]{x}}{a}\right )^3 \left (a^2+2 a b \sqrt [3]{x}+b^2 x^{2/3}\right )^p}{b^9 (3+2 p)}-\frac {84 a^9 \left (1+\frac {b \sqrt [3]{x}}{a}\right )^4 \left (a^2+2 a b \sqrt [3]{x}+b^2 x^{2/3}\right )^p}{b^9 (2+p)}+\frac {210 a^9 \left (1+\frac {b \sqrt [3]{x}}{a}\right )^5 \left (a^2+2 a b \sqrt [3]{x}+b^2 x^{2/3}\right )^p}{b^9 (5+2 p)}-\frac {84 a^9 \left (1+\frac {b \sqrt [3]{x}}{a}\right )^6 \left (a^2+2 a b \sqrt [3]{x}+b^2 x^{2/3}\right )^p}{b^9 (3+p)}+\frac {84 a^9 \left (1+\frac {b \sqrt [3]{x}}{a}\right )^7 \left (a^2+2 a b \sqrt [3]{x}+b^2 x^{2/3}\right )^p}{b^9 (7+2 p)}-\frac {12 a^9 \left (1+\frac {b \sqrt [3]{x}}{a}\right )^8 \left (a^2+2 a b \sqrt [3]{x}+b^2 x^{2/3}\right )^p}{b^9 (4+p)}+\frac {3 a^9 \left (1+\frac {b \sqrt [3]{x}}{a}\right )^9 \left (a^2+2 a b \sqrt [3]{x}+b^2 x^{2/3}\right )^p}{b^9 (9+2 p)} \]
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Rubi [A]
time = 0.16, antiderivative size = 468, normalized size of antiderivative = 1.00, number of steps
used = 4, number of rules used = 3, integrand size = 28, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.107, Rules used = {1370, 272, 45}
\begin {gather*} \frac {3 a^9 \left (\frac {b \sqrt [3]{x}}{a}+1\right )^9 \left (a^2+2 a b \sqrt [3]{x}+b^2 x^{2/3}\right )^p}{b^9 (2 p+9)}-\frac {12 a^9 \left (\frac {b \sqrt [3]{x}}{a}+1\right )^8 \left (a^2+2 a b \sqrt [3]{x}+b^2 x^{2/3}\right )^p}{b^9 (p+4)}+\frac {84 a^9 \left (\frac {b \sqrt [3]{x}}{a}+1\right )^7 \left (a^2+2 a b \sqrt [3]{x}+b^2 x^{2/3}\right )^p}{b^9 (2 p+7)}-\frac {84 a^9 \left (\frac {b \sqrt [3]{x}}{a}+1\right )^6 \left (a^2+2 a b \sqrt [3]{x}+b^2 x^{2/3}\right )^p}{b^9 (p+3)}+\frac {210 a^9 \left (\frac {b \sqrt [3]{x}}{a}+1\right )^5 \left (a^2+2 a b \sqrt [3]{x}+b^2 x^{2/3}\right )^p}{b^9 (2 p+5)}-\frac {84 a^9 \left (\frac {b \sqrt [3]{x}}{a}+1\right )^4 \left (a^2+2 a b \sqrt [3]{x}+b^2 x^{2/3}\right )^p}{b^9 (p+2)}+\frac {84 a^9 \left (\frac {b \sqrt [3]{x}}{a}+1\right )^3 \left (a^2+2 a b \sqrt [3]{x}+b^2 x^{2/3}\right )^p}{b^9 (2 p+3)}-\frac {12 a^9 \left (\frac {b \sqrt [3]{x}}{a}+1\right )^2 \left (a^2+2 a b \sqrt [3]{x}+b^2 x^{2/3}\right )^p}{b^9 (p+1)}+\frac {3 a^9 \left (\frac {b \sqrt [3]{x}}{a}+1\right ) \left (a^2+2 a b \sqrt [3]{x}+b^2 x^{2/3}\right )^p}{b^9 (2 p+1)} \end {gather*}
Antiderivative was successfully verified.
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Rule 45
Rule 272
Rule 1370
Rubi steps
\begin {align*} \int \left (a^2+2 a b \sqrt [3]{x}+b^2 x^{2/3}\right )^p x^2 \, dx &=\left (\left (1+\frac {b \sqrt [3]{x}}{a}\right )^{-2 p} \left (a^2+2 a b \sqrt [3]{x}+b^2 x^{2/3}\right )^p\right ) \int \left (1+\frac {b \sqrt [3]{x}}{a}\right )^{2 p} x^2 \, dx\\ &=\left (3 \left (1+\frac {b \sqrt [3]{x}}{a}\right )^{-2 p} \left (a^2+2 a b \sqrt [3]{x}+b^2 x^{2/3}\right )^p\right ) \text {Subst}\left (\int x^8 \left (1+\frac {b x}{a}\right )^{2 p} \, dx,x,\sqrt [3]{x}\right )\\ &=\left (3 \left (1+\frac {b \sqrt [3]{x}}{a}\right )^{-2 p} \left (a^2+2 a b \sqrt [3]{x}+b^2 x^{2/3}\right )^p\right ) \text {Subst}\left (\int \left (\frac {a^8 \left (1+\frac {b x}{a}\right )^{2 p}}{b^8}-\frac {8 a^8 \left (1+\frac {b x}{a}\right )^{1+2 p}}{b^8}+\frac {28 a^8 \left (1+\frac {b x}{a}\right )^{2+2 p}}{b^8}-\frac {56 a^8 \left (1+\frac {b x}{a}\right )^{3+2 p}}{b^8}+\frac {70 a^8 \left (1+\frac {b x}{a}\right )^{4+2 p}}{b^8}-\frac {56 a^8 \left (1+\frac {b x}{a}\right )^{5+2 p}}{b^8}+\frac {28 a^8 \left (1+\frac {b x}{a}\right )^{6+2 p}}{b^8}-\frac {8 a^8 \left (1+\frac {b x}{a}\right )^{7+2 p}}{b^8}+\frac {a^8 \left (1+\frac {b x}{a}\right )^{8+2 p}}{b^8}\right ) \, dx,x,\sqrt [3]{x}\right )\\ &=\frac {3 a^9 \left (1+\frac {b \sqrt [3]{x}}{a}\right ) \left (a^2+2 a b \sqrt [3]{x}+b^2 x^{2/3}\right )^p}{b^9 (1+2 p)}-\frac {12 a^9 \left (1+\frac {b \sqrt [3]{x}}{a}\right )^2 \left (a^2+2 a b \sqrt [3]{x}+b^2 x^{2/3}\right )^p}{b^9 (1+p)}+\frac {84 a^9 \left (1+\frac {b \sqrt [3]{x}}{a}\right )^3 \left (a^2+2 a b \sqrt [3]{x}+b^2 x^{2/3}\right )^p}{b^9 (3+2 p)}-\frac {84 a^9 \left (1+\frac {b \sqrt [3]{x}}{a}\right )^4 \left (a^2+2 a b \sqrt [3]{x}+b^2 x^{2/3}\right )^p}{b^9 (2+p)}+\frac {210 a^9 \left (1+\frac {b \sqrt [3]{x}}{a}\right )^5 \left (a^2+2 a b \sqrt [3]{x}+b^2 x^{2/3}\right )^p}{b^9 (5+2 p)}-\frac {84 a^9 \left (1+\frac {b \sqrt [3]{x}}{a}\right )^6 \left (a^2+2 a b \sqrt [3]{x}+b^2 x^{2/3}\right )^p}{b^9 (3+p)}+\frac {84 a^9 \left (1+\frac {b \sqrt [3]{x}}{a}\right )^7 \left (a^2+2 a b \sqrt [3]{x}+b^2 x^{2/3}\right )^p}{b^9 (7+2 p)}-\frac {12 a^9 \left (1+\frac {b \sqrt [3]{x}}{a}\right )^8 \left (a^2+2 a b \sqrt [3]{x}+b^2 x^{2/3}\right )^p}{b^9 (4+p)}+\frac {3 a^9 \left (1+\frac {b \sqrt [3]{x}}{a}\right )^9 \left (a^2+2 a b \sqrt [3]{x}+b^2 x^{2/3}\right )^p}{b^9 (9+2 p)}\\ \end {align*}
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Mathematica [A]
time = 0.20, size = 207, normalized size = 0.44 \begin {gather*} \frac {3 \left (\frac {a^8}{1+2 p}-\frac {4 a^7 \left (a+b \sqrt [3]{x}\right )}{1+p}+\frac {28 a^6 \left (a+b \sqrt [3]{x}\right )^2}{3+2 p}-\frac {28 a^5 \left (a+b \sqrt [3]{x}\right )^3}{2+p}+\frac {70 a^4 \left (a+b \sqrt [3]{x}\right )^4}{5+2 p}-\frac {28 a^3 \left (a+b \sqrt [3]{x}\right )^5}{3+p}+\frac {28 a^2 \left (a+b \sqrt [3]{x}\right )^6}{7+2 p}-\frac {4 a \left (a+b \sqrt [3]{x}\right )^7}{4+p}+\frac {\left (a+b \sqrt [3]{x}\right )^8}{9+2 p}\right ) \left (a+b \sqrt [3]{x}\right ) \left (\left (a+b \sqrt [3]{x}\right )^2\right )^p}{b^9} \end {gather*}
Antiderivative was successfully verified.
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Maple [F]
time = 0.00, size = 0, normalized size = 0.00 \[\int \left (a^{2}+2 a b \,x^{\frac {1}{3}}+b^{2} x^{\frac {2}{3}}\right )^{p} x^{2}\, dx\]
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A]
time = 0.30, size = 362, normalized size = 0.77 \begin {gather*} \frac {3 \, {\left ({\left (16 \, p^{8} + 288 \, p^{7} + 2184 \, p^{6} + 9072 \, p^{5} + 22449 \, p^{4} + 33642 \, p^{3} + 29531 \, p^{2} + 13698 \, p + 2520\right )} b^{9} x^{3} + {\left (16 \, p^{8} + 224 \, p^{7} + 1288 \, p^{6} + 3920 \, p^{5} + 6769 \, p^{4} + 6566 \, p^{3} + 3267 \, p^{2} + 630 \, p\right )} a b^{8} x^{\frac {8}{3}} - 8 \, {\left (8 \, p^{7} + 84 \, p^{6} + 350 \, p^{5} + 735 \, p^{4} + 812 \, p^{3} + 441 \, p^{2} + 90 \, p\right )} a^{2} b^{7} x^{\frac {7}{3}} + 28 \, {\left (8 \, p^{6} + 60 \, p^{5} + 170 \, p^{4} + 225 \, p^{3} + 137 \, p^{2} + 30 \, p\right )} a^{3} b^{6} x^{2} - 168 \, {\left (4 \, p^{5} + 20 \, p^{4} + 35 \, p^{3} + 25 \, p^{2} + 6 \, p\right )} a^{4} b^{5} x^{\frac {5}{3}} + 420 \, {\left (4 \, p^{4} + 12 \, p^{3} + 11 \, p^{2} + 3 \, p\right )} a^{5} b^{4} x^{\frac {4}{3}} - 1680 \, {\left (2 \, p^{3} + 3 \, p^{2} + p\right )} a^{6} b^{3} x + 2520 \, {\left (2 \, p^{2} + p\right )} a^{7} b^{2} x^{\frac {2}{3}} - 5040 \, a^{8} b p x^{\frac {1}{3}} + 2520 \, a^{9}\right )} {\left (b x^{\frac {1}{3}} + a\right )}^{2 \, p}}{{\left (32 \, p^{9} + 720 \, p^{8} + 6960 \, p^{7} + 37800 \, p^{6} + 126546 \, p^{5} + 269325 \, p^{4} + 361840 \, p^{3} + 293175 \, p^{2} + 128322 \, p + 22680\right )} b^{9}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 0.48, size = 579, normalized size = 1.24 \begin {gather*} \frac {3 \, {\left (2520 \, a^{9} + {\left (16 \, b^{9} p^{8} + 288 \, b^{9} p^{7} + 2184 \, b^{9} p^{6} + 9072 \, b^{9} p^{5} + 22449 \, b^{9} p^{4} + 33642 \, b^{9} p^{3} + 29531 \, b^{9} p^{2} + 13698 \, b^{9} p + 2520 \, b^{9}\right )} x^{3} + 28 \, {\left (8 \, a^{3} b^{6} p^{6} + 60 \, a^{3} b^{6} p^{5} + 170 \, a^{3} b^{6} p^{4} + 225 \, a^{3} b^{6} p^{3} + 137 \, a^{3} b^{6} p^{2} + 30 \, a^{3} b^{6} p\right )} x^{2} - 1680 \, {\left (2 \, a^{6} b^{3} p^{3} + 3 \, a^{6} b^{3} p^{2} + a^{6} b^{3} p\right )} x + {\left (5040 \, a^{7} b^{2} p^{2} + 2520 \, a^{7} b^{2} p + {\left (16 \, a b^{8} p^{8} + 224 \, a b^{8} p^{7} + 1288 \, a b^{8} p^{6} + 3920 \, a b^{8} p^{5} + 6769 \, a b^{8} p^{4} + 6566 \, a b^{8} p^{3} + 3267 \, a b^{8} p^{2} + 630 \, a b^{8} p\right )} x^{2} - 168 \, {\left (4 \, a^{4} b^{5} p^{5} + 20 \, a^{4} b^{5} p^{4} + 35 \, a^{4} b^{5} p^{3} + 25 \, a^{4} b^{5} p^{2} + 6 \, a^{4} b^{5} p\right )} x\right )} x^{\frac {2}{3}} - 4 \, {\left (1260 \, a^{8} b p + 2 \, {\left (8 \, a^{2} b^{7} p^{7} + 84 \, a^{2} b^{7} p^{6} + 350 \, a^{2} b^{7} p^{5} + 735 \, a^{2} b^{7} p^{4} + 812 \, a^{2} b^{7} p^{3} + 441 \, a^{2} b^{7} p^{2} + 90 \, a^{2} b^{7} p\right )} x^{2} - 105 \, {\left (4 \, a^{5} b^{4} p^{4} + 12 \, a^{5} b^{4} p^{3} + 11 \, a^{5} b^{4} p^{2} + 3 \, a^{5} b^{4} p\right )} x\right )} x^{\frac {1}{3}}\right )} {\left (b^{2} x^{\frac {2}{3}} + 2 \, a b x^{\frac {1}{3}} + a^{2}\right )}^{p}}{32 \, b^{9} p^{9} + 720 \, b^{9} p^{8} + 6960 \, b^{9} p^{7} + 37800 \, b^{9} p^{6} + 126546 \, b^{9} p^{5} + 269325 \, b^{9} p^{4} + 361840 \, b^{9} p^{3} + 293175 \, b^{9} p^{2} + 128322 \, b^{9} p + 22680 \, b^{9}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-2)]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: HeuristicGCDFailed} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] Leaf count of result is larger than twice the leaf count of optimal. 1564 vs.
\(2 (414) = 828\).
time = 4.00, size = 1564, normalized size = 3.34 \begin {gather*} \text {Too large to display} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 3.52, size = 777, normalized size = 1.66 \begin {gather*} {\left (a^2+b^2\,x^{2/3}+2\,a\,b\,x^{1/3}\right )}^p\,\left (\frac {3\,x^3\,\left (16\,p^8+288\,p^7+2184\,p^6+9072\,p^5+22449\,p^4+33642\,p^3+29531\,p^2+13698\,p+2520\right )}{32\,p^9+720\,p^8+6960\,p^7+37800\,p^6+126546\,p^5+269325\,p^4+361840\,p^3+293175\,p^2+128322\,p+22680}+\frac {7560\,a^9}{b^9\,\left (32\,p^9+720\,p^8+6960\,p^7+37800\,p^6+126546\,p^5+269325\,p^4+361840\,p^3+293175\,p^2+128322\,p+22680\right )}-\frac {15120\,a^8\,p\,x^{1/3}}{b^8\,\left (32\,p^9+720\,p^8+6960\,p^7+37800\,p^6+126546\,p^5+269325\,p^4+361840\,p^3+293175\,p^2+128322\,p+22680\right )}+\frac {3\,a\,p\,x^{8/3}\,\left (16\,p^7+224\,p^6+1288\,p^5+3920\,p^4+6769\,p^3+6566\,p^2+3267\,p+630\right )}{b\,\left (32\,p^9+720\,p^8+6960\,p^7+37800\,p^6+126546\,p^5+269325\,p^4+361840\,p^3+293175\,p^2+128322\,p+22680\right )}+\frac {84\,a^3\,p\,x^2\,\left (8\,p^5+60\,p^4+170\,p^3+225\,p^2+137\,p+30\right )}{b^3\,\left (32\,p^9+720\,p^8+6960\,p^7+37800\,p^6+126546\,p^5+269325\,p^4+361840\,p^3+293175\,p^2+128322\,p+22680\right )}-\frac {5040\,a^6\,p\,x\,\left (2\,p^2+3\,p+1\right )}{b^6\,\left (32\,p^9+720\,p^8+6960\,p^7+37800\,p^6+126546\,p^5+269325\,p^4+361840\,p^3+293175\,p^2+128322\,p+22680\right )}-\frac {24\,a^2\,p\,x^{7/3}\,\left (8\,p^6+84\,p^5+350\,p^4+735\,p^3+812\,p^2+441\,p+90\right )}{b^2\,\left (32\,p^9+720\,p^8+6960\,p^7+37800\,p^6+126546\,p^5+269325\,p^4+361840\,p^3+293175\,p^2+128322\,p+22680\right )}+\frac {7560\,a^7\,p\,x^{2/3}\,\left (2\,p+1\right )}{b^7\,\left (32\,p^9+720\,p^8+6960\,p^7+37800\,p^6+126546\,p^5+269325\,p^4+361840\,p^3+293175\,p^2+128322\,p+22680\right )}+\frac {1260\,a^5\,p\,x^{4/3}\,\left (4\,p^3+12\,p^2+11\,p+3\right )}{b^5\,\left (32\,p^9+720\,p^8+6960\,p^7+37800\,p^6+126546\,p^5+269325\,p^4+361840\,p^3+293175\,p^2+128322\,p+22680\right )}-\frac {504\,a^4\,p\,x^{5/3}\,\left (4\,p^4+20\,p^3+35\,p^2+25\,p+6\right )}{b^4\,\left (32\,p^9+720\,p^8+6960\,p^7+37800\,p^6+126546\,p^5+269325\,p^4+361840\,p^3+293175\,p^2+128322\,p+22680\right )}\right ) \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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